2021-05-18 / 2021-05-18 / Python

Python 100 题 - Day03

Question 10

Question

Write a program that accepts a sequence of whitespace separated words as input and prints the words after removing all duplicate words and sorting them alphanumerically.

Suppose the following input is supplied to the program:

hello world and practice makes perfect and hello world again

Then, the output should be:

again and hello makes perfect practice world

Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.We use set container to remove duplicated data automatically and then use sorted() to sort the data.

Main author's Solution: Python 2

s = raw_input()
words = [word for word in s.split(" ")]
print " ".join(sorted(list(set(words))))

My Solution: Python 3

word = input().split()

for i in word:
    if word.count(i) > 1:    #count function returns total repeatation of an element that is send as argument
        word.remove(i)     # removes exactly one element per call

word.sort()
print(" ".join(word))

word = input().split()
[word.remove(i) for i in word if word.count(i) > 1 ]   # removal operation with comprehension method
word.sort()
print(" ".join(word))

word = sorted(list(set(input().split())))              #  input string splits -> converting into set() to store unique
                                                       #  element -> converting into list to be able to apply sort
print(" ".join(word))

'''Solution by: Sukanya-Mahapatra
'''
inp_string = input("Enter string: ").split()
out_string = []
for words in inp_string:
    if words not in out_string:
        out_string.append(words)
print(" ".join(sorted(out_string)))

Question 11

Question

Write a program which accepts a sequence of comma separated 4 digit binary numbers as its input and then check whether they are divisible by 5 or not. The numbers that are divisible by 5 are to be printed in a comma separated sequence.

Example:

0100,0011,1010,1001

Then the output should be:

Notes: Assume the data is input by console.

Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.

Main author's Solution: Python 2

value = []
items=[x for x in raw_input().split(',')]
for p in items:
    intp = int(p,2)
    if not intp % 5:
        value.append(p)

print ','.join(value)

My Solution: Python 3

def check(x):                       # converts binary to integer & returns zero if divisible by 5
    total,pw = 0,1
    reversed(x)

    for i in x:
        total+=pw * (ord(i) - 48)   # ord() function returns ASCII value
        pw*=2
    return total % 5

data = input().split(",")           # inputs taken here and splited in ',' position
lst = []

for i in data:
    if check(i) == 0:               # if zero found it means divisible by zero and added to the list
        lst.append(i)

print(",".join(lst))

def check(x):                   # check function returns true if divisible by 5
    return int(x,2)%5 == 0      # int(x,b) takes x as string and b as base from which
                                # it will be converted to decimal
data = input().split(',')

data = list(filter(check,data)) # in filter(func,object) function, elements are picked from 'data' if found True by 'check' function
print(",".join(data))

data = input().split(',')
data = list(filter(lambda i:int(i,2)%5==0,data))    # lambda is an operator that helps to write function of one line
print(",".join(data))

'''Solution by: nikitaMogilev
'''
data = input().split(',')
data = [num for num in data if int(num, 2) % 5 == 0]
print(','.join(data))

'''Solution by: hajimalung baba
'''
print(*(binary for binary in input().split(',') if int(binary,base=2)%5==0))

Question 12

Question:

Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each digit of the number is an even number.The numbers obtained should be printed in a comma-separated sequence on a single line.

Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.

Main author's Solution: Python 2

values = []
for i in range(1000, 3001):
    s = str(i)
    if (int(s[0])%2 == 0) and (int(s[1])%2 == 0) and (int(s[2])%2 == 0) and (int(s[3])%2 == 0):
        values.append(s)
print ",".join(values)

My Solution: Python 3

lst = []

for i in range(1000,3001):
    flag = 1
    for j in str(i):          # every integer number i is converted into string
        if ord(j)%2 != 0:     # ord returns ASCII value and j is every digit of i
            flag = 0          # flag becomes zero if any odd digit found
    if flag == 1:
        lst.append(str(i))    # i is stored in list as string

print(",".join(lst))

def check(element):
    return all(ord(i)%2 == 0 for i in element)  # all returns True if all digits i is even in element

lst = [str(i) for i in range(1000,3001)]        # creates list of all given numbers with string data type
lst = list(filter(check,lst))                   # filter removes element from list if check condition fails
print(",".join(lst))

lst = [str(i) for i in range(1000,3001)]
lst = list(filter(lambda i:all(ord(j)%2 == 0 for j in i), lst))   # using lambda to define function inside filter function
print(",".join(lst))

'''Solution by: nikitaMogilev
'''
# map() digits of each number with lambda function and check if all() of them even
# str(num) gives us opportunity to iterate through number by map() and join()
print(','.join([str(num) for num in range(1000, 3001) if all(map(lambda num: int(num) % 2 == 0, str(num)))]))

'''Solution by: hajimalung
'''
from functools import reduce 
#using reduce to check if the number has only even digits or not
def is_even_and(bool_to_compare,num_as_char):
    return int(num_as_char)%2==0 and bool_to_compare

print(*(i for i in range(1000,3001) if reduce(is_even_and,str(i),True)),sep=',')

Question 13

Question:

Write a program that accepts a sentence and calculate the number of letters and digits.

Suppose the following input is supplied to the program:

hello world! 123

Then, the output should be:

LETTERS 10
DIGITS 3

Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.

Main author's Solution: Python 2

s = raw_input()
d = {"DIGITS":0, "LETTERS":0}
for c in s:
    if c.isdigit():
        d["DIGITS"]+=1
    elif c.isalpha():
        d["LETTERS"]+=1
    else:
        pass
print "LETTERS", d["LETTERS"]
print "DIGITS", d["DIGITS"]

My Solution: Python 3

word = input()
letter,digit = 0,0

for i in word:
    if ('a'<=i and i<='z') or ('A'<=i and i<='Z'):
        letter+=1
    if '0'<=i and i<='9':
        digit+=1

print("LETTERS {0}\nDIGITS {1}".format(letter,digit))

word = input()
letter, digit = 0,0

for i in word:
    if i.isalpha(): # returns True if alphabet
        letter += 1
    elif i.isnumeric(): # returns True if numeric
        digit += 1
print(f"LETTERS {letter}\n{digits}") # two different types of formating method is shown in both solution

''' Solution by: popomaticbubble
'''
import re

input_string = input('> ')
print()
counter = {"LETTERS":len(re.findall("[a-zA-Z]", input_string)), "NUMBERS":len(re.findall("[0-9]", input_string))}

print(counter)

'''Solution by: MarkisLandis
'''

sen = input("").split(" ")
alp, digit = 0, 0

for item in sen:
    lst = [char for char in item]
    for j in lst:
        if 64 < ord(j) < 123:
            alp += 1
        if j.isdigit():
            digit += 1
print(f"LETTERS : {alp} \n DIGITS : {digit}")

'''Solution by: hajimalung
'''
#using reduce for to count
from functools import reduce

def count_letters_digits(counters,char_to_check):
    counters[0] += char_to_check.isalpha()
    counters[1] += char_to_check.isnumeric()
    return counters

print('LETTERS {0}\nDIGITS {1}'.format(*reduce(count_letters_digits,input(),[0,0])))

Conclusion

All the above problems are mostly string related problems. Major parts of the solution includes string releted functions and comprehension method to write down the code in more shorter form.

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